Python program to find sum of squares of first n natural numbers; In this tutorial, you will learn how to find sum of squares of first n natural numbers in python using for loop and mathematical formula.
Python Program for Sum of squares of first n natural numbers
There are the following python programs to to find sum of squares of first n (50, 100, 1000) natural numbers; as shown below:
- Python program to find sum of squares of first n natural numbers using for loop
- Python program to find sum of squares of first n natural numbers using mathmatic formula
Python program to find sum of squares of first n natural numbers using for loop
Use the following steps and write a program to find the sum of squares of the first n natural numbers:
- Take input number from the user
- Calculate the sum of square of given N number using for loop
- Display sum of square of n given number
# Python program for sum of the # square of first N natural numbers # Getting input from users N = int(input("Enter value of N: ")) # calculating sum of square sumVal = 0 for i in range(1, N+1): sumVal += (i*i) print("Sum of squares = ", sumVal)
Output
Enter value of N: 10 Sum of squares = 385
Python program to find sum of squares of first n natural numbers using mathmatic formula
Use the following steps and write a program to find the sum of squares of the first n natural numbers:
- Take input number from the user
- Calculate the sum of square of the n given number using mathmatic formula
- Display sum of square of n given number
# Python program for sum of the # square of first N natural numbers # Getting input from user N = int(input("Enter value of N: ")) # calculating sum of square sumVal = (int)( (N * (N+1) * ((2*N) + 1))/6 ) print("Sum of squares =",sumVal)
Output
Enter value of N: 12 Sum of squares = 650
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