Python Program to Find Number of Integers From 1 to n Contains Digits 0’s

Python program to find and count the number of occurrences of 0’s in integers from 1 to N; In this tutorial, you will learn how to find and count integers from 1 to N contain 0’s and 1’s as digits.

How to check if a number contains 0’s digit From 1 to N in python

• Python Program 1: Find the number of integers from 1 to n which contains digits 0’s
• Python Program 2: Find the number of integers from 1 to n which contains digits 0’s
• Python Program 3: Find the number of integers from 1 to n which contains digits 0’s and 1’s

Python Program 1: Find the number of integers from 1 to n which contains digits 0’s

# Python Program to Find the number of integers from 1 to n which contains digits 0's

# input the value of N
n=int(input('Enter the value of n: '))

s=str(n)
z=str(0)

if z in s:
    print('Zero is found in {}'.format(n))
else:
    print('Zero is not found in {}'.format(n))

Output

Enter the value of n:  10
Zero is found in 10

Python Program 2: Find the number of integers from 1 to n which contains digits 0’s

# Python Program to Find the number of integers from 1 to n which contains digits 0's

# enter the value of N
n=int(input('Enter the value of n: '))

c=0
z=str(0)

for j in range(1,n+1):
    if z in str(j):
        c+=1
print('{} number has zero as digits up to {}.'.format(c,n))

Output

Enter the value of n:  50
5 number has zero as digits up to 50.

Python Program 3: Find the number of integers from 1 to n which contains digits 0’s and 1’s

# Python Program to Find the number of integers
# from 1 to n which contains 0's and 1's only

n=int(input('Enter the value of n: '))

def countNumbers(x, n):

	# If number is greater than n
	if x > n :
		return 0

	# otherwise add count this number and
	# call two functions
	return (1 + countNumbers(x * 10, n) +
				countNumbers(x * 10 + 1, n))

# Driver code
if __name__ == '__main__':

	print('The count is ', countNumbers(1, n)); 

Output

Enter the value of n:  200
The count is  7

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